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log1/3(1/2)=log3(2) 对吗 为什么

log1/2(2/3) =log1/2(2)-log1/2(3) =-1+lg2(3) =-1+1.585 =0.585

y = √ { log (1/3) [(3+2x-x2)]} 首先,零和负数无对数,所以3+2x-x2>0,(x+1)(x-3)<0,-1<x<3 第二,根号下无负数,∴ log (1/3) [(3+2x-x2)]>0,∴3+2x-x2<1,x2-2x+1<3,(x-1)2<3,1-√3<x<1+√3 ∴1-√3<x<1+√3

=lg0.5/lg3=-0.301/0.477=-0.631

对,这两个是相等的

a=log(1/2) =log(1/2) /log(1/3) =log2 b=log(2/3) = log (2/3) /log(1/2) = (1- log2)/log2 =-1+ 1/log2 c= log (4/3) =-1+ log4 =-1+ 2log2 c- a = -1+ log2 a> c log 2 >0.5 c-b =2log2 - 1/log2 >0 => c>b ie a>c>b

换底公式怎么写知道吧?将底换成1/3,左边分母就成了log1/3(1/3)/log1/3(1/2)

a>b>c

=1/2的(log2[3]) =1/3 这里用到a^loga(N)=N

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