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log2(3)*log3(4)=?

2^[log4(3)] =2^[log2^2(3)] =2^[lg3/lg2^2] =2^(lg3/2lg2) =2^[(1/2)*log2(3)] =2^[log2(√3)] =√3

log2+log3=log6 如下图所示,是“4”的第一个公式的逆运算

log2(3)-log4(6) = log2(3)-log2^2((√6)^2) = log2(3)-log2(√6) = log2(3/√6) = log2(√3/√2) = log2(√3)-log2(√2) = 1/2log2(3) - 1/2 如果题目是【log2(3)-log4(36)】 log2(3)-log4(36) = log2(3)-log2^2((6)^2) = log2(3)-log2(6) = log2(3/6)...

log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8) =log2(3)*log2(4)/log2(3)*log2(5)/log2(4)*...*log2(8)/log2(7) =log2(8)=3

(log3 2+log9 2)*(log4 3+log8 3) =(lg2/lg3+lg2/lg9)*(lg3/lg4+lg3/lg8) =(lg2/lg3+lg2/2lg3)*(lg3/2lg2+lg3/3lg2 =3/2*lg2/lg3*5/6*lg3/lg2 =3/2*5/6=5/4

是×还是比大小 ×的话:原式=(lg25/lg2)×(lg4/lg3)×(lg9/lg5) =(2lg5/lg2)×(2lg2/lg3)×(2lg3/lg5) =8 比大小的话:log2 16

原式 =(lg25/lg2)*(lg4/lg3)*(lg9/lg5) =(lg25/lg5)*(lg4/lg2)*(lg9/lg3) =2*2*2 =8

别说=(lg25/lg2)×(lg4/lg3)×(lg9/lg5) =(2lg5/lg2)×(2lg2/lg3)×(2lg3/lg5) =8 确实是这一个,你的是错误的 本题用了两个公式 一个是换底公式loga b=lgb/lga 另一个是指数的对数 loga b^m=mloga b 如果本题有什么不明白可以追问,如果满意记得采...

都换成以2为底的对数进行比较 log2(3)=log2(根号9) log4(5)=log2(根号5) 3/2=log2(2^(3/2))=log2(根号8) 因为y=log2(x)在(0,+无穷)上为增函数 所以log2(3)>3/2>log4(5)

1/4*log3(2)+4×llog3(2)=㏒3(2的开四次方)+log3(2的四次方)=2×log3(2)

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