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log3(9)=2? 为什么啊

换底公式:loga(b)=logc(b)/logc(a) 左边换成以3为底 =log3(2)/log3(9)=右边

log(老哥)以三为底九的对数等于二!望采纳!谢谢!

log(3)9=log(3)3^2 =2log(3)3 =2x1 =2.

2^(2+log2 3)+3^(2-log3 9) =2^2*2^(log2 3)+3^2/3^(log3 9) =4*3+9/9 =12+1 =13

解析 可以这么来做 log3 9^(-1) =-log3 9 =-2 希望对你有帮助 学习进步O(∩_∩)O谢谢

log3 4/log9 8 =2*log3 2/[(3/2)*log3 2] =2/(3/2) =4/3 loga^b(c^d)=d/bloga(c)

log2 12-log2 4=log2 (12/3)=log2 3

2log3(2)-log3(32/9)+log3(8)-5^log5(3) =log3(4)-log3(32/9)+log3(8)-3 =log3(4*8)-log3(32/9)-3 =log3(32)-log3(32/9)-3 =log3(32/(32/9))-3 =log3(9)-3 =2-3 =-1

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