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python中rEquEsts请求超时 异常怎么书写

用下面这段代码试试: NETWORK_STATUS = True try: requests.get('https://www.taobao.com/', timeout=0.1) except requests.exceptions.ConnectTimeout: NETWORK_STATUS = False print(NETWORK_STATUS)

用下面这段代码试试: NETWORK_STATUS = True try: requests.gettimeout=0.1) except requests.exceptions.ConnectTimeout: NETWORK_STATUS = False print(NETWORK_STATUS)

import sys import requestsif len(sys.argv) != 2: print "Usage: python %s " % (sys.argv[0]) sys.exit(); InputFile = sys.argv[1] try: File = open(InputFile) for ip in File: IP = ip.rstrip() out = requests.get("http://" + IP, time...

超时你可以告诉 requests 在经过以 timeout 参数设定的秒数时间之后停止等待响应:>>> requests.get('http://github.com', timeout=0.001)Traceback (most recent call last): File "", line 1, in requests.exceptions.Timeout: HTTPConnection...

415是HTTP协议的状态码 415的含义是不支持的媒体类型(Unsupported media type) 检查是否在POST请求中加入了header header中是否包含了正确的Content-Type

#python 3+import requeststry: requests.get(url="")except TimeoutError as e: # 捕获超时异常 print(e)

用下面这段代码试试: NETWORK_STATUS = True try: requests.get/', timeout=0.1) except requests.exceptions.ConnectTimeout: NETWORK_STATUS = False print(NETWORK_STATUS)

try: requests.get('', timeout=0.1) except requests.exceptions.ConnectTimeout: NETWORK_STATUS = False except requests.exceptions.Timeout: REQUEST_TIMEOUT = TRUE

用下面这段代码试试: NETWORK_STATUS = True try: requests.get('https://www.taobao.com/', timeout=0.1) except requests.exceptions.ConnectTimeout: NETWORK_STATUS = False print(NETWORK_STATUS)

古柏行(杜甫)

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